Solving Differentiation Help: Find Time When Acceleration = 0

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SUMMARY

The discussion focuses on finding the time when the acceleration of a particle, described by the velocity function v = 10sin(1/2 t), equals zero. The correct approach involves differentiating the velocity function to obtain the acceleration, represented as dv/dt = 5cos(1/2 t). Setting this equal to zero leads to the equation cos(1/2 t) = 0, which is solved to find that the first time when acceleration is zero occurs at t = π seconds, not at 1/2π as initially miscalculated.

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Differentiation Help!

Homework Statement


A particle is moving along a straight line so that, at time t seconds after leaving a fixed point O, its velocity vms-1 is given by v=10sin(1/2 t).
Find the time when the acceleration, given by dv/dt, is first zero.

Homework Equations


sinx differentiates to cosx

The Attempt at a Solution


Ok i know they are asking me to find the time where there is a stationary point so therefore the gradient or dv/dt = 0.
From differentiating 10sin(1/2 t) i got 5cos(1/2 t). so therefore, 5cos(1/2 t)=0 so i thought you multiply by 2 to get rid of the half then divide by 10 so the Right hand side= 0 and then inverse cos of 0 = 1/2 Pi but the answer in the textbook gives Pi.
Please help me any body!
 
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You've got the steps right, just note that it's 1/2t = arc cos 0 and not t = arc cos 0.
 


ohhh yeah of course! thank you very much =]
 

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