Solving Elevator Problem: Physics Student in Accelerating Elevator

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SUMMARY

The discussion centers on calculating the reading of a bathroom scale when a physics student accelerates downward in an elevator at 1.97 m/s². Initially, the scale reads 564 N when the elevator is stationary. To find the scale reading during the downward acceleration, one must apply Newton's second law (F=ma) and consider the net force acting on the student, which combines their weight and the force due to acceleration. The correct approach involves drawing a free-body diagram and calculating the effective weight during the acceleration.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with free-body diagrams
  • Basic knowledge of forces and weight calculations
  • Ability to apply F=ma in different scenarios
NEXT STEPS
  • Study free-body diagram techniques for analyzing forces
  • Learn about the effects of acceleration on weight readings
  • Explore advanced applications of Newton's laws in non-inertial frames
  • Review examples of similar physics problems involving elevators and acceleration
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding dynamics in non-inertial reference frames, particularly in real-world applications like elevators.

sheri1987
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Homework Statement


A physics student stands on a bathroom scale in an elevator which is not moving. The scale reads 564 N. The elevator then accelerates downward at 1.97 m/s2. What does the scale read during this acceleration?



Homework Equations



F=ma, W=mg

The Attempt at a Solution



I thought at first the answer should be 0 N, but that is wrong...then I tried using Newton's 2nd Law F = 564 N, a = 1.97, but when I plugged this in it was stilled wrong...what equation should I use?
 
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You are using the correct formulae, but are not looking at the whole situation. First, draw yourself a diagram; then consider what force would be required to make the student accelerate downwards at 1.97m/s^2. Finally, you need to figure out how you combine this force with the weight of the student.
 

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