Mathematica Solving equation and plotting issue with Mathematica

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The discussion centers on solving a complex function for the variable r and plotting the results using Mathematica. The user is attempting to solve the equation related to a function involving parameters a, Q, c, M, P, and ω, but is encountering errors that prevent them from generating plots. They seek assistance in identifying potential mistakes in their approach, noting the absence of error messages or warnings. The conversation suggests checking Mathematica forums for support, as they have a community focused on such issues. Additionally, a user referenced a simpler version of the problem that was successfully solved using the ParametricPlot command, indicating that there may be alternative methods to achieve the desired outcome.
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I have a function ##f(\text{r})\text{=}-\frac{a Q^4}{20 r^6}-\frac{c}{r^{3 \omega +1}}-\frac{2 M}{r}+\frac{8}{3} \pi P r^2+\frac{Q^2}{r^2}+1;## and an expression $$\text{Tinv2}=\frac{2^{2/3} \pi ^{4/3} a Q^4}{9 \sqrt[3]{3} V^{7/3}}+c 2^{2 \omega -\frac{2}{3}} \left(\frac{3}{\pi }\right)^{\frac{1}{3}-\omega } \omega V^{-\omega -\frac{2}{3}}+\sqrt[3]{\frac{6}{\pi }} P \sqrt[3]{V}-\frac{Q^2}{3 V}+\frac{1}{2 \sqrt[3]{6} \pi ^{2/3} \sqrt[3]{V}};$$. Now I want to solve r from $$-5 a Q^4-6 c \omega (3 \omega +5) r^{5-3 \omega }-4 r^4 \left(8 \pi P-3 Q^2+2 r^2\right)=0$$ and use it to obtain plot for Tinv2. Then I want to solve for r from ##f(r)=0## and use it to plot another function. Now I am getting error and obtained no plots. Can any one tell me where am I doing mistake and how can I fix it? Please follow the link here for the detailed question and notebook.
 
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There's little to go on with no error or warning text. In addition, we are not a Mathematica end-user forum, so it's unlikely someone at PF will recognize where you went off the rails with your code.

Have you tried to check the Mathematica forums?

You'll find a supportive community of people who are keenly interested in Mathematica problems and solutions. They're there to help you, so don't hesitate to reach out.
 

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