Solving equation containing absolute values

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SUMMARY

The equation |2x+7| - |6-3x| = 8 can be solved by considering three cases based on the sign of the expressions within the absolute values. The first case involves both expressions being positive, while the second considers one positive and one negative, and the third case addresses both being negative. The solutions for the equation include x = 7/5, x = -15/2, and x = ½, with the necessity to validate solutions against the defined cases to ensure they fall within the correct ranges.

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  • Familiarity with case analysis in problem-solving
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jkristia
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Homework Statement



I have this equation

|2x+7| - |6-3x| = 8.

The step I did is to replace the || with () and then solve the equation
2x+7-6+3x = 8
X = 7/5

But how do a go about solving for the second solution?
With one absolute value I would
|2x + 7| = 8
2x + 7 = +-8
2x = -7 +-8
X = -15/2, x = ½

But I can’t see how to solve the first equation for the second solution.
 
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The best way to approach this type of problem is to take 3 cases.

Firstly, you need to find at which x value each absolute value is positive or negative. 2x+7>0, then x>-7/2, thus for x>-7/2 that expression is positive and for x<-7/2 that expression is negative.
6-3x>0, x<2, thus for x<2 it is positive, and x>2 it is negative.

Now the first case you should consider is for all x values such that both expressions are positive.
The next case should be for x values where one is positive and the other is negative.
The last case should be when both are negative.

As an example, if we have to solve |x|+|x-1|=2, for x>1 both are positive, so we simply solve x+(x-1)=2, for 0<x<1 we have the first being positive and the second being negative, thus we solve x-(x-1)=2 and for x<0 both are negative so we solve -x-(x-1)=2.

Just apply the same idea to your question.

p.s. remember that since we assumed x<0 for the last case, the solution needs to be less than zero, else it is an invalid solution and you just discard it.
 
I think I got it, thank you for your help.
 

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