Solving equations by inversion formulae

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SUMMARY

The discussion centers on solving the equation f(x) = 0 using inversion formulae, particularly through the application of Lagrange's inversion theorem. It highlights that multi-valued functions, such as x², can present challenges due to their multiple branches. The theorem provides a method to find unique solutions in a local neighborhood, but its limitations are noted, specifically regarding the radius of convergence and the uniqueness of solutions derived from different locations in the power series.

PREREQUISITES
  • Understanding of Lagrange's inversion theorem
  • Familiarity with multi-valued functions and their branches
  • Knowledge of power series and convergence
  • Basic calculus, particularly differentiation
NEXT STEPS
  • Study the applications of Lagrange's inversion theorem in various mathematical contexts
  • Explore the properties and behavior of multi-valued functions
  • Investigate the concept of radius of convergence in power series
  • Learn about alternative methods for solving equations with multiple solutions
USEFUL FOR

Mathematicians, students studying advanced calculus, and anyone interested in the theoretical aspects of solving equations using inversion techniques.

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the idea is let us suppose i must solve

[tex]f(x)= 0[/tex] (1)

let us suppose that f(x) have SEVERAL (perhaps infinite ) inverses, that is there is a finite or infinite solutions to the equation

[tex]f(x)= y[/tex] by [tex]g(y)= x[/tex] with [tex]f^{-1}(x)=g(x)[/tex]

then solution to equation (1) would be [tex]g(0)=x[/tex]

my problem is what would happen for multi-valued functions (example [tex]x^{2}[/tex] having several 'branches' (is this the correct word ?? )

Using Lagrange inversion theorem [tex]g(x) = a<br /> + \sum_{n=1}^{\infty}<br /> \left(<br /> \lim_{w \to a}\left(<br /> \frac{\mathrm{d}^{\,n-1}}{\mathrm{d}w^{\,n-1}}<br /> \left( \frac{w-a}{f(w) - b} \right)^n\right)<br /> {\frac{(x - b)^n}{n!}}<br /> \right).[/tex]

then simply set x=0 but this would only give an UNIQUE solution to (1)
 
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Lagrange's inversion theorem is a local theorem, i.e. it is only valid in a neighborhood depending on the radius of convergence - different locations result in different power series.
 

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