# Solving first and second degree equations

1. May 23, 2016

### late347

1. The problem statement, all variables and given/known data

solve the equations below

1.) 2x -1 = (1/2) *x +3

and

2) 1/x - 4/ x2= 0

2. Relevant equations
3. The attempt at a solution

2x -1 = 0,5x +3

2x= 0,5x +4
1,5x = 4
x= 4/ 1,5
x= 8/3

my math teacher told me that the x= 8/6 would have been correct solution to this first one

1/x -4/ x2 = 0

1/x = 4/x2

we enlarge the fraction 1/x

x/ x2 = 4/ x2

multiply both sides by x2

x= 4

singular solution assuming that originally x is unequal to 0 (because cannot divide with 0)

my teacher told me that this latter equation has twin solutions either x=-4 or x= 4

plugging -4 into the original equation, this seems not true at all...

-0,25 -( 0,25) = 0

-0,5 = 0

untrue.

2. May 23, 2016

### ehild

3. May 23, 2016

### late347

Thank you for prompt response. It looks like even math teachers make silly mistakes sometimes. Twice in this problem sheet.

Can you take a gander at my other thread about algebra problem that I had. I just posted a simple word problem in the same precalculus homework math subrofum

4. May 23, 2016

### ehild

I see you solved it.

5. May 23, 2016

### SteamKing

Staff Emeritus
Time to find another math teacher.