Solving for Acceleration: 8.3kg Block & 25.3° Angle

[chaotixmonjuish]

A block of mass 8.3 kg is pulled along a horizontal frictionless floor by a cord that exerts a force of 53.0 N at an angle 25.3° above the horizontal. What is the magnitude of the acceleration of the block?

I'm just wondering how I set up an equation with an angle.

 

[bel]

Separate the applied force into its horizontal and vertical components using the trigonometric ratios or use the method of tension co-efficients.

 

[chaotixmonjuish]

That's where I'm having a problem.

would it be something like:

y=(mass)(sin(30)a)
x=(mass)(cos(30)a)

 

[bel]

How about $$F_x = F(cos (\frac{\pi}{6}))$$ ?

 

[chaotixmonjuish]

wow, how did you get that

 

[HallsofIvy]

That's where I'm having a problem.

would it be something like:

y=(mass)(sin(30)a)
x=(mass)(cos(30)a)

Yes, something like that. But of course the angle isn't 30 degrees.