Solving for Acceleration in a Moving Railroad Car: Newton's Law Explained

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SUMMARY

The discussion focuses on calculating the acceleration of a railroad car using Newton's laws of motion. A 3kg object suspended from a rope at a 4-degree angle indicates the car's acceleration, which is determined to be 0.69 m/s². Key equations used include T*cos(θ) = mg and ma = T*sin(θ). The solution involves combining these equations to derive the acceleration from the tension in the rope.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of trigonometric functions (sine and cosine)
  • Ability to draw and interpret free body diagrams
  • Familiarity with basic physics concepts related to tension and forces
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  • Study the application of Newton's laws in non-inertial reference frames
  • Learn how to resolve forces using trigonometric identities
  • Explore advanced topics in dynamics, such as friction and inclined planes
  • Practice solving problems involving tension in various contexts
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of applying Newton's laws in real-world scenarios.

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Homework Statement



A 3kg object hangs at one end of a rope that is attached to a the ceiling of a railroad car. When the car accelerates to the right, the rope makes an angle of 4 degrees with the vertical. Find the acceleration of the car.
the answer is 0.69m/s^2

Homework Equations



sigma F=ma, tension*cos(theta) = mg, Fnet - ma = 0
yup. looks good to me. but I don't what values to plug in.

The Attempt at a Solution



First I draw free body diagram. gravity acts on the string. And I thought I could make some equation like Fsin(delta) like sort of thing by drawing triangle with 4 degree and...oh, I got all messed up.
I tried to use an equation :tension*cos(theta) = mg
plug value: tension*cos(4)=3.0x9.81 I think I can figure out what the tension is. However,
I do not know how to get the acceleration.
will you please help me?
I would be very appreciated if you give me specific procedure how the answer came out by giving information about what equation was used and so forth. Thanks!
 
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The first equation you found is correct:

[tex]T \cos \theta =mg[/tex]

Using Newton's second law you should also be able to show that:

[tex]ma=T sin \theta[/tex]

Combine the two equations to find [tex]a[/tex].
 
My, I didn't know this can be solved so easily. I remember my teacher said about it, but I lost my note. When I followed your advice and used the equation i am given, I got my result 0.685! Thank you so much. Have a nice day =)
 

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