Solving for Equal Capacitors in Parallel: Potential of Each

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SUMMARY

When two equal capacitors are connected in parallel, the potential across each capacitor becomes the same. For a charged capacitor with potential V and a discharged capacitor, the final potential of each capacitor is V/sqrt(2). However, energy conservation does not apply due to energy loss through resistive wires during charge movement. The total charge is conserved, and the correct approach involves calculating the total charge and capacitance when connected.

PREREQUISITES
  • Understanding of capacitor theory and parallel connections
  • Familiarity with energy equations, specifically E=1/2 (C.V^2)
  • Knowledge of charge conservation principles
  • Basic circuit analysis involving resistive components
NEXT STEPS
  • Study the principles of charge conservation in electrical circuits
  • Learn about energy loss in resistive circuits
  • Explore advanced capacitor configurations and their effects on potential
  • Investigate the implications of connecting capacitors in series versus parallel
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone looking to deepen their understanding of capacitor behavior in parallel circuits.

vipulsilwal
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Homework Statement


2 capacitors of equal capacitance one charged to potential V, and other completely discharged. when the are connected in parallel what would be the potential of each one of them.

Homework Equations



E=1/2 (C.V^2)

The Attempt at a Solution


as they are connected in parallel potential of each wud be same... now by conservation of energy i got answer V/sqrt(2)
am i right??
 
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vipulsilwal said:

Homework Statement


2 capacitors of equal capacitance one charged to potential V, and other completely discharged. when the are connected in parallel what would be the potential of each one of them.

Homework Equations



E=1/2 (C.V^2)

The Attempt at a Solution


as they are connected in parallel potential of each wud be same... now by conservation of energy i got answer V/sqrt(2)
am i right??
What is the charge, Q, on the charged capacitor (in terms of C and V)?
What is the total charge, Q', on the two capacitors when they are connected together?
What is the capacitance, C', of the two capacitors when connected together (in terms of C)?
What is the potential V' (in terms of Q' and C')?
Now express the answer in terms of C and V.

AM
 
When you connect the two capacitors in parallel, energy will be lost due to the charges moving through the resistive wires. So conservation of energy doesn't apply in this case. But the total number of charges is conserved. So follow Andrew Mason's steps and you will get the right answer.
 

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