Solving for f',f'',f''' and determining a general formula

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The discussion highlights the importance of following instructions in mathematical problems, specifically in finding derivatives. It points out that the user only calculated the first two derivatives, f'(x) and f''(x), without completing the task of finding f'''(x) and f^{IV}(x). The correct derivatives are noted as f'''(x) = 2^3 e^{2x} and f^{IV}(x) = 2^4 e^{2x}. Additionally, the nth derivative at a specific point is provided as f^{(n)}(1/2) = 2^n e. Completing all derivative calculations is essential for a comprehensive solution.
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Can someone confirm if my work is correct?
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I'm a bit surprised you did not do what you were asked to do! The problem specifically asked you to "find f'(x), f''(x), f'''(x), and f^{IV}(x) then the nth derivative but you have only found f'(x) and f''(x) before jumping to the nth derivative.
Other than the fact that you do not have f'''(x)= 2^3 e^{2x} and f^{IV}(x)= 2^4e^{2x}, every thing is good!
 
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The problem also mentions "or ##f^{(n)}\left( \tfrac{1}{2}\right)##", which is of course ##\boxed{f^{(n)}\left( \tfrac{1}{2}\right) = 2^n e}##.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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