Solving for F2 in the Turning Effect of Force Problem

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Homework Help Overview

The discussion revolves around a problem related to the turning effect of forces, specifically focusing on finding the force F2 in a static equilibrium scenario involving a slab and cables. Participants are exploring the concepts of center of mass and the application of torque equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to determine the location of the center of mass of the slab and how to calculate the total downward force exerted by the cables. Questions about the specific distances and relationships between forces and distances in the context of static equilibrium are raised.

Discussion Status

The discussion is active, with participants providing insights and clarifications regarding the center of mass and the relationships between the forces involved. Some guidance has been offered regarding the application of torque equations, but there is no explicit consensus on the next steps.

Contextual Notes

Participants are navigating through the problem with some initial confusion about the distances involved and the definitions of the forces. The original poster expresses difficulty in making progress, indicating a need for further clarification on the concepts at play.

Muhammad Danish
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Homework Statement


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Homework Equations



How will we find the perpendicular distance between the wall and the centre of mass of the slab? How will we calculate the total downward force exerted by the cables on the slab? I thought much over both the cases but was not able to find any solution. Your explanations will be seriously appreciable.

The Attempt at a Solution


Not able to make any attempt.[/B]
 

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Where do you think the centre of mass of the slab is located?
 
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kuruman said:
Where do you think the centre of mass of the slab is located?
Between 2.5 m and 0.5 m
 
Muhammad Danish said:
Between 2.5 m and 0.5 m
At the top of the wall I mean..
 
Muhammad Danish said:
Between 2.5 m and 0.5 m
Can you be more specific? If I were to draw a line parallel to the long dimension of the concrete slab and perpendicular to the 3.0 m side, at what distance from where the cables are attached would I have to draw it so that it passes through the CM? The answer to this question is the answer to part (a). Have you done this much?
 
Muhammad Danish said:
At the top of the wall I mean..
kuruman said:
Can you be more specific? If I were to draw a line parallel to the long dimension of the concrete slab and perpendicular to the 3.0 m side, at what distance from where the cables are attached would I have to draw it so that it passes through the CM? The answer to this question is the answer to part (a). Have you done this much?
Since the slab is 3.0 m wide, the center of mass should lie at 1.5 m from the side. Am I right?
 
You are right. That's the answer to part (a). You can assume that the external force of gravity acts at the CM. This is a static equilibrium problem. Do you know how to proceed with problems of this kind?
 
Muhammad Danish said:
the center of mass should lie at 1.5 m from the side.

kuruman said:
That's the answer to part (a)
Not quite... the question asks for the distance from the wall, not the side of the slab.
 
haruspex said:
Not quite... the question asks for the distance from the wall, not the side of the slab.
Yes, of course. Thanks for pointing this out.
 
  • #10
haruspex said:
Not quite... the question asks for the distance from the wall, not the side of the slab.
Distance from the wall will be 1.5 - 0.5 = 1 ?
 
  • #11
Muhammad Danish said:
Distance from the wall will be 1.5 - 0.5 = 1 ?
Yes, 1 m to be precise. Do you know where to go next in this static equilibrium problem?
 
  • #12
kuruman said:
Yes, 1 m to be precise. Do you know where to go next in this static equilibrium problem?
To calculate downward force will we use the formula F1D1 = F2D2 ?
 
  • #13
Muhammad Danish said:
To calculate downward force will we use the formula F1D1 = F2D2 ?
That looks about right for this case. What do you think F1, D1,F2 and D2 stand for? To use this equation you need numbers for three of them, the fourth one being the unknown. What are the three numbers?
 
  • #14
kuruman said:
That looks about right for this case. What do you think F1, D1,F2 and D2 stand for? To use this equation you need numbers for three of them, the fourth one being the unknown. What are the three numbers?
They will be, F1= 18000 N, D1= 1 m and F2= ?, D2= 0.5 m ?
 
  • #15
Muhammad Danish said:
They will be, F1= 18000 N, D1= 1 m and F2= ?, D2= 0.5 m ?
Yes. Now can you solve for F2?
 
  • #16
jbriggs444 said:
Yes. Now can you solve for F2?
Yes. Thanks.
 

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