Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Introductory Physics Homework Help
Solving for final position with a negative work value
Reply to thread
Message
[QUOTE="Selayna, post: 4965282, member: 537339"] [h2]Homework Statement [/h2] An object is acted on by the force shown in the picture shown below: [ATTACH=full]175205[/ATTACH] What is the final position of the object if its initial position is [I]x[/I] = 0.50 m and the work done on it is equal to -0.29 J? Initial position = Xi = 0.5 m Work = W = -0.29 J Force = F displacement = d Final position = Xf = ? m [h2]Homework Equations[/h2] W = F(d - Xi) + F(d-d) + F(Xf - d) W = Fd [h2]The Attempt at a Solution[/h2] [/B] I worked on the first part of this problem, where work was equal to 0.12 J and the initial position was 0.5 m, using this equation: 0.12 = 0.8(0.5 - 0.5) + 0.4(0.75-0.5) + 0.2(Xf - 0.75) I assumed, since W = Fd, and displacement can't have a negative value, Force would have to have a negative value to get a negative value for Work. Using this logic, I modified the original equation to use a negative Force: W = -F(d - Xi) - F(d-d) - F(Xf - d) Using this equation, I went through these steps: 1. Plug in values -0.29 = -0.8(0.5 - 0.5) - 0.4(0.75-0.5) - 0.2(Xf - 0.75) 2. Reduce -0.29 = 0 - 0.1 + 0.15 - 0.2Xf 3. Subtract 0.15 and add 0.1 to both sides -0.34 = -0.2Xf 4. Divide both sides by 0.2 1.7 = Xf However, the answer I got for the final position (1.7), was incorrect. I'm assuming my initial logic using negative values for force was incorrect, but I'm not sure how else I would solve the problem with a negative work value. Any help is appreciated. Thanks! [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Introductory Physics Homework Help
Solving for final position with a negative work value
Back
Top