Where, λ1 = -3.2 μC/cm, λ2 = 9.6 μC/cm, a = 8.5 cm and h = 11.4 cm. a/2 = 4.25 cm.
What is the total flux that passes through the surface of the cylinder?
E = 2kλ/r
[itex]\Phi[/itex] = E*A = qenclosed/[itex]\epsilon[/itex]o
The Attempt at a Solution
The first thing I did was solve for the total electric field of the two line charges, which is 338823529.411765 N/C. After this, the next step would be to simply multiply by the surface area of the cylinder. However, this doesn't work because the electric field is not constant throughout the surface of the cylinder.
My next step was to try and solve it using the enclosed charge, but since I have only been given the charge densities of each line, I have no clue how to figure out enclosed charge. Is there a specific method as to how you can do this?
Any help is greatly appreciated.
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