Solving for Force Given Rotational Inertia and Mass

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Homework Help Overview

The discussion revolves around a problem involving a rotating disk and a hanging mass, focusing on the forces acting on the system and the relationships between mass, acceleration, and rotational inertia. The subject area includes dynamics and rotational motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants examine the forces acting on the disk and the hanging mass, questioning the application of Newton's second law and the correct formulation of the equations of motion. There is a focus on identifying the correct contributors to the force balance and the implications of the assumptions made.

Discussion Status

The discussion is active, with participants providing feedback on each other's reasoning and calculations. Some guidance has been offered regarding the correct interpretation of forces and the need to clarify variable usage. Multiple interpretations of the force balance are being explored.

Contextual Notes

Participants are addressing potential errors in the original poster's equations and assumptions, particularly regarding the forces acting on the disk and the relationship between tension and acceleration. There is an acknowledgment of the complexity of the problem and the need for careful consideration of the system's dynamics.

MathewsMD
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A 0.70-kg disk with a rotational inertia given by MR2/2 (M) is free to rotate on a fixed horizontal axis suspended from the ceiling. A string is wrapped around the disk and a 2.0-kg mass (m) hangs from the free end. If the string does not slip, then as the mass falls and the cylinder rotates, the suspension holding the cylinder pulls up on the cylinder with a force of:

A. 6.9N
B. 9.8N
C. 16N
D. 26N
E. 29N
ans: B

My solution:

ma = mg - F
Fr = Ia/r
mg - ma = Ia/r2

mg - ma = Ma/2

a = (mg)/(m + 0.5M)

ƩFy = FN - Mg - Ma

FN = M (g + a) = ~9.77N

Please point out any errors since I really want to ensure I understood every process throughly and correctly. If you have anything to add, in terms of helpful steps or things to consider in general, please reply! :)
 
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You were doing well until here:
MathewsMD said:
ƩFy = FN - Mg - Ma
Look at the free body diagram for the disk (cylinder?).
Where is there an Ma in there?
 
[ignore/]
 
Last edited:
zahbaz said:
"ƩFy = FN - Mg - Ma"

Another way to ask what haruspex is getting at:
What does ƩFy equal? Meaning, do we have acceleration or are the sum of y forces zero?

Sorry, I meant to add ƩFy = 0, isn't that a correct assumption?
 
MathewsMD said:
Sorry, I meant to add ƩFy = 0, isn't that a correct assumption?

Yes, but you don't have the right contributors to ƩFy.
 
Ohh... yeah, that's a totally correct assumption. I misread the scenario!

I got the same answer, 9.77... but not sure where you have the Ma term as haruspex mentioned. If you consider the mass is falling with F = ma, how much tension remains on the line? This is a downwards force on the cylinder.

ƩFy = FN - Mg - tension
 
Okay, thank your for clearing that up. Yes, I used the wrong variable name but calculated it as ma was tension.
 
MathewsMD said:
Okay, thank your for clearing that up. Yes, I used the wrong variable name but calculated it as ma was tension.
OK, so you meant ƩFy = FN - Mg - m(g-a), right?
But in the next line of the OP you wrote M (g + a), which is not so easily explained?
 

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