Solving for Magnetic Flux in a Square Loop

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SUMMARY

The discussion focuses on calculating magnetic flux in a square loop subjected to a magnetic field of 3.0 T at a 55-degree angle. The initial calculation using the equation MFlux = BACos(theta) yielded a result of 0.11 Wb, which was questioned by the user. The correct approach involves using the equation MFlux = BAsin(theta) due to the angle being with the plane of the coil, leading to a more accurate calculation of magnetic flux.

PREREQUISITES
  • Understanding of magnetic fields and their properties
  • Familiarity with the concept of magnetic flux
  • Knowledge of trigonometric functions, specifically sine and cosine
  • Ability to manipulate equations involving physical constants
NEXT STEPS
  • Review the derivation of the magnetic flux formula MFlux = BAsin(theta)
  • Explore examples of magnetic flux calculations in different geometries
  • Learn about the implications of angles in electromagnetic theory
  • Study the applications of magnetic flux in real-world scenarios, such as electric generators
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone involved in solving problems related to magnetic fields and flux calculations.

louza8
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Homework Statement



A 3.0 magnetic field makes a 55deg angle with a square loop 25cm on a side

Homework Equations



MFlux = BACos(theta)

The Attempt at a Solution



=3*.252*cos(55)
=0.11Wb

Answer is to 2 sigfigs. This is a masteringphysics problem, and I'm wondering if I'm missing something here or if MP has the wrong answer stored.
 
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The relevant equation given by you is for a field making an angle θ with the vertical.

In the problem the angle is with the plane of the coil. So

MFlux = BAsinθ.
 
thanks
 

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