Solving for Moles of Ions in 0.0200g AgNO3

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SUMMARY

The discussion focuses on calculating the number of moles of ions in 0.0200g of silver nitrate (AgNO3). To determine the moles, one must first calculate the molar mass of AgNO3, which is approximately 169.87 g/mol. Using the formula for moles, moles = mass (g) / molar mass (g/mol), the calculation yields 0.000117 moles of AgNO3. Since AgNO3 dissociates into three ions (one Ag+ and two NO3-), the total moles of ions in the solution is 0.000351 moles.

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How many moles of ions are in 0.0200g AgNO3. Please help, i can't seem to set up the equation!
 
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0.2g - how many moles of AgNO3?

How do you calculate number of moles of substance given mass and formula?
 

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