Solving for perimeter and dimensions of a rectangle

  • Thread starter Lancelot59
  • Start date
  • #1
Lancelot59
646
1
I understand calculus, I just don't understand how it is applied to solve these sorts of problems.

Homework Statement


What is the smallest perimeter for a rectangle with an area of 16, and what are its dimensions?


Homework Equations


A=L*W
P=2W+2L

The Attempt at a Solution



I managed to get the perimeter equation down to one variable like so:

Area is 16.

A=LW
16=LW
16/L=W

P=2L+2(16/L)
P=(2L2+32)/L

and this is where I stop. I just don't see how this can be applied to the situation stated.
 

Answers and Replies

  • #2
danago
Gold Member
1,123
4
Well you now have a function, P, of just one variable, L. You want to find when this function is a minimum? Have you been shown how to find the minimum points of a function using calculus?
 
  • #3
Lancelot59
646
1
Yes I have.

I need to look for locations where the first derivative is zero and the second derivative is positive on both sides of the critical point.

I'm just having a tricky time actually applying calculus to these situations.
 
  • #4
danago
Gold Member
1,123
4
Ok. The easiest way to do these types of problems is probably to first find all of the critical point of the function (i.e. where the derivative is zero or undefined). From there, you can then check whether the critical point(s) you find are local maximums/minimums or inflections by evaluating the second derivative at those points.
 
  • #5
HallsofIvy
Science Advisor
Homework Helper
43,021
970
I understand calculus, I just don't understand how it is applied to solve these sorts of problems.

Homework Statement


What is the smallest perimeter for a rectangle with an area of 16, and what are its dimensions?


Homework Equations


A=L*W
P=2W+2L

The Attempt at a Solution



I managed to get the perimeter equation down to one variable like so:

Area is 16.

A=LW
16=LW
16/L=W

P=2L+2(16/L)
P=(2L2+32)/L

and this is where I stop. I just don't see how this can be applied to the situation stated.

Yes I have.

I need to look for locations where the first derivative is zero and the second derivative is positive on both sides of the critical point.

I'm just having a tricky time actually applying calculus to these situations.
Perhaps because you are not trying! What is the derivative of P= 2L+ 32/L? Where is that derivative 0?
 
  • #6
mist42nz
1
0
P=(2L^2+32)/L

Where do you get the power of 2?

"P=2L+2(16/L)
P=(2L2+32)/L" ??

P=2L+2(16/L)
P=2(L+16/L)

or

2L+32/L
L+16/L
 

Suggested for: Solving for perimeter and dimensions of a rectangle

Replies
4
Views
266
  • Last Post
Replies
12
Views
155
Replies
0
Views
197
Replies
7
Views
624
Replies
3
Views
255
Replies
1
Views
407
Replies
8
Views
670
Replies
7
Views
373
  • Last Post
Replies
1
Views
594
Top