Solving for Slowest Speed of a Ball: 2.25m Radius

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Homework Help Overview

The problem involves determining the slowest speed of a ball with a radius of 2.25 m at the bottom of a circular path, specifically to ensure it can complete the circular motion at the top of the path.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express confusion about the problem statement and its requirements. There is an emphasis on understanding the dynamics involved, particularly through the use of free body diagrams and Newton's second law.

Discussion Status

Some participants have begun to clarify their understanding of the problem and have made initial attempts to apply relevant physics concepts. Guidance has been offered regarding the use of diagrams and equations, though there is still some uncertainty about the correct application of these concepts.

Contextual Notes

There is a noted lack of clarity in the initial problem statement, which has led to confusion among participants. The discussion includes attempts to reconstruct the problem based on partial information provided.

liz777
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Homework Statement


A ball has a radius of 2.25 m. What is the slowest speed of the ball at the bottom which will just make it around at the top of the path?

The Attempt at a Solution



I don't even know where to start with this problem. I don't understand it. Any help would be greatly appreciated!
 
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liz777 said:
I don't even know where to start with this problem. I don't understand it.

Neither do I, because you didn't type in the entire problem statement. I'm guessing that the ball is tethered to a rope of radius 2.25 m, but that's just a guess. Please type in the problem statement exactly as it appears on your assignment.
 
oh sorry...here it is:

When one spins a ball in a circular path which has a radius of 2.25 m, what is the slowest speed of the ball at the bottom which will just make it around at the top of the path?
 
You should begin by drawing a free body diagram of the ball at the top of its path. Then write down Newton's second law for the ball at that point. That's how you start all dynamics problems at this level.
 
ok, I drew a diagram and I think I understand. Gravity pulls down on the ball, which is the acceleration so:
v^2=gr
=(9.8)(2.25)

Is this correct?
 
Right, just remember to take the square root. You found v^2, not v.
 
ok, thank you! :) I understand it.
 

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