Solving for t and h when both are unknown.

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SUMMARY

The discussion focuses on solving for the time (t) and height (h) of an object falling under gravity, specifically when it travels 0.51h in the last second of its fall. The key equations involved are acceleration due to gravity (a = -g) and the height formula (h = 0.5gt²). The approach suggested includes dividing the fall into two segments: t1 for the initial part and t2 = 1 second for the last part, allowing for the calculation of average velocity and distance traveled. This method leads to a system of equations that can be solved to find both unknowns.

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BUConsul
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Okay, so this question has really gotten under my skin.

"An object falls a distance h from rest. If it travels 0.51h in the last 1.00 s, find (a) the time and (b) the height of its fall."

I have some groundwork laid out: a=-g, h=.5gt^2, and that between two points 1 second apart the average velocity is .51h(m/s). The only problem is I end up with equations that are in terms of unknowns 't' and 'h'. I know I lam probably missing something painfully obvious, and I'd appreciate any help I can get. Also, if it's not to much trouble, some hints versus the actual solution would be appreciated. (I'd like to do as much as possible, how else can I learn?)
Thanks in Advance - David
 
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Divide the falling time in two, so that it takes t1 seconds to fall the first part and t2=1sec to fall the last part. Then you can give an expression for the velocity at the start of the last part use this combined with the acceleration to make a formula for the distance traveled during the last part and equate that formula with the known height (0.51h) that is traveled during the last part.
 

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