Solving for Theta, wolfram doesn't give anything useful

[physstudent.4]

Homework Statement

I need to write a function of theta in terms of a particular variable. I just can't seem to figure it out; the only solution I can come up with is when the aforementioned variable is equal to 0 or 1. I'm using Q to denote theta, and b is the variable.

sin^3(Q)/cos(Q)=b^2

Homework Equations

Any and all trig identities.
I've used sin^2(x)+cos^(x)=1, sin(2x)=2sin(x)cos(x), I haven't stumbled into any work that led me to use other identities!

The Attempt at a Solution

Around 5 pages of scratch work, all for naught.
Any relevant trig identities I might be missing would be nice to know, if anyone figures this out soon! Thanks!

 

[SammyS]

Homework Statement

I need to write a function of theta in terms of a particular variable. I just can't seem to figure it out; the only solution I can come up with is when the aforementioned variable is equal to 0 or 1. I'm using Q to denote theta, and b is the variable.

sin^3(Q)/cos(Q)=b^2

Homework Equations

Any and all trig identities.
I've used sin^2(x)+cos^(x)=1, sin(2x)=2sin(x)cos(x), I haven't stumbled into any work that led me to use other identities!

The Attempt at a Solution

Around 5 pages of scratch work, all for naught.
Any relevant trig identities I might be missing would be nice to know, if anyone figures this out soon! Thanks!

sin³(θ)/cos(θ) = 1/(cot(θ)csc²(θ)) = 1/(cot(θ)+cot³(θ))

but I don't think this will help all that much.

 

[Dick]

You can reduce it to a polynomial equation. Square both sides. Replace cos(Q)^2 by 1-sin(Q)^2. Now let P=sin(Q)^2. You'll get a cubic equation in P. You CAN solve a cubic exactly, but the solutions are so complicated as to be almost useless. You will have a little advantage here because there is no P^2 term. But it's still pretty complicated. Stuff like this is usually handled numerically, not analytically.