- #1

- 2

- 0

THETA = 30a

or somehow get the 'a' on the left hand side?

Equation:

THETA = arccos(1 - 0.005a)

Those aren't the exact numbers/arrangement I'm working with but any help would be greatly appreciated.

- Thread starter calky117
- Start date

- #1

- 2

- 0

THETA = 30a

or somehow get the 'a' on the left hand side?

Equation:

THETA = arccos(1 - 0.005a)

Those aren't the exact numbers/arrangement I'm working with but any help would be greatly appreciated.

- #2

eumyang

Homework Helper

- 1,347

- 10

It would be better if you posted the original problem instead of using numbers and/or an arrangement that isn't exact. Are you trying to solve for

THETA = 30a

or somehow get the 'a' on the left hand side?

Equation:

THETA = arccos(1 - 0.005a)

Those aren't the exact numbers/arrangement I'm working with but any help would be greatly appreciated.

- #3

- 2

- 0

From the above the unknown is 'x' which is what I want to solve for (again I have skipped out a lot of the working that is irrelevant to you).

If I substitute in THETA to the area 'A' equation then put that into the equation on the bottom I get a huge awful looking equation, only the one unknown but I just don't know how to solve for it. Any guidance please?

- #4

Mark44

Mentor

- 33,706

- 5,401

You solved for [itex]\theta/2[/itex], but didn't solve for x.

To isolate x (i.e., solve for x), multiply both sides of the original equation by 150. Then add -150 to both sides. Finally, divide both sides by -.77 to get x all by itself.

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