Solving for Vo: Graph Analysis of Vs vs t

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SUMMARY

The discussion focuses on graphing the output voltage (Vo) using the equation Vs=Vi(1-e^-t/T). The user is tasked with determining how to plot Vo over time intervals ranging from -0.1s to 0.5s, given that Vo is set to 1 Volt. The key takeaway is that the graph should reflect the specified time intervals, ensuring that tick marks align with the original graph's structure. Additionally, the user is encouraged to consider smaller time increments for more precise plotting.

PREREQUISITES
  • Understanding of exponential decay functions in electrical circuits
  • Familiarity with graphing techniques for voltage vs. time
  • Knowledge of the time constant (T) in RC circuits
  • Basic proficiency in using graphing software or tools
NEXT STEPS
  • Explore the implications of varying the time constant (T) in voltage decay
  • Learn about graphing software options for precise voltage-time plots
  • Investigate the significance of tick marks and intervals in data representation
  • Study the effects of different initial voltages (Vi) on the output graph
USEFUL FOR

Students studying electrical engineering, educators teaching circuit analysis, and anyone involved in graphing voltage behavior in RC circuits.

Marcin H
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Homework Statement


Screen Shot 2016-02-15 at 8.02.45 PM.png


Homework Equations


Vs=Vi(1-e^-t/T)

The Attempt at a Solution


I am stuck on B. I am not sure how I am supposed to graph Vo with so little information. Do i just use V=Vo(1-e^-t/T) and find the output voltage for each time increment that is on the original graph. So Vo=1Volt and we have T and we just find voltages from t=-.1s to t=.5s? And then we graph voltage out vs time?
 
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That's right - but why stick to the time intervals shown on the graph, why not choose much smaller intervals?
You may be expected to make sure the tick-marks on the graph match the picture.
 

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