ΔU = -q∫E * ds
The Attempt at a Solution
Just by looking at the graph I am thinking, if I solve for E using the equation above, the number would be always negative therefore I can conclude that the electric field at any x position would be negative and the graph will look the same it will be just inverted. (-y values)
I don't know if this is the correct way to look at the problem or if I have to use energy conservation but any help would be much appreciated.