Solving Friction Problem 3: Initial Velocity of Object

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Homework Help Overview

The problem involves determining the initial velocity of an object that comes to a stop due to friction over a distance of 12.3 meters, with a given coefficient of static friction of 0.5. The context is rooted in dynamics and frictional forces.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Newton's second law and kinematic equations but expresses confusion about how to find acceleration without an applied force. Some participants suggest considering the work-energy principle as a simpler approach, while others question the formulation of the force equation used by the original poster.

Discussion Status

Participants are exploring different methods to approach the problem, with some guidance provided regarding the net force being the force of friction. There is an acknowledgment of a potential solution by one participant, but explicit consensus on the correctness of the calculations has not been reached.

Contextual Notes

There is a discussion about the relevance of mass in this scenario, with one participant noting that it does not affect the outcome due to the nature of the forces involved. Additionally, the original poster's confusion about the application of forces indicates a need for clarification on the problem setup.

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Homework Statement


An object takes 12.3 meters to stop because of friction. Assume no skidding. If the coefficient of static friction is 0.5, what is the initial velocity of the object?




2. The attempt at a solution
My teacher said that in this task the mass doesn't matter, so we would have
##F_{net}=ma##
##F-ug=a##
The object is on motion and we need to find v0 so we would have
##v_0^2=v_f^2-2ax##.
Now for this we need the acceleration, so
##a=F-ug##, I have the coefficient and the gravity, but no applying force, so how can I find the acceleration, and how will I find the v0, If I have no acceleration?
 
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Do you know about the work/energy relation?
If you do this problem becomes a lot simpler.

Regarding your attempt;
What is this F you have in your force equation
[itex]F-ug=a[/itex]
From the conditions given I don't see what other external force is being applied other than that friction.
 
Sorry for double posting I think I got it:
In this case the force of friction is the net force so (thanks to genericusrnme)
##ug=a##
##=0.5(9.81\frac{m}{s^2})=a##
##4.905\frac{m}{s^2}=a##
##v_0^2=v^2-2ax##
##v_0^2=0\frac{m^2}{s^2} - 2(4.905\frac{m}{s^2})(12.3m)##
##v_0^2=-120.663\frac{m}{s}## (to the left)
##v_0=\sqrt{120.663}##
##v_0=10.98467113754436\frac{m}{s}##
Is that right?
 
Last edited:
Yes, that is correct
 

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