Solving Gauss' Law for Electric Field Around Spherical Shell

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radiator0505
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Homework Statement


a spherical shell has an outer radius R and a inner radius R/2 and carries a total charge -q, distributed with uniform charge density. A point charge +q is at the centre of the sphere. Calculate the electric field strength for R/2<r<R

Homework Equations



Gauss' Law

The Attempt at a Solution



I figured out the charge density in the shell ρ = [itex]\frac{-6q}{7πR^3}[/itex], so the charge enclosed by a gaussian sphere is q(1-[itex]\frac{8r^3}{7R^3}[/itex])

Then using gauss' law I get E = [itex]\frac{q}{4πε_0r^2}[/itex](1-[itex]\frac{8r^3}{7R^3}[/itex])

But my book says E = [itex]\frac{q}{4πε_0r^2}[/itex][itex]\frac{8}{7}[/itex](1-[itex]\frac{r^3}{R^3}[/itex])Also does anyone know why the latex things aren't working? I'm new to all this stuff.

Edit: cheers guys
 
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radiator0505 said:
Also does anyone know why the latex things aren't working? I'm new to all this stuff.


Don't use the BB code tags like inside the LaTeX code. If you want to do superscripts in the LaTex math code, use ^ .
 
radiator0505 said:
Also does anyone know why the latex things aren't working? I'm new to all this stuff.
Could be that you're combining Latex with non-Latex stuff. Stick to pure Latex and it should work.
 
radiator0505 said:
I figured out the charge density in the shell ρ = [itex]\frac{-6q}{7πR^3}[/itex],
Good.

so the charge enclosed by a gaussian sphere is q(1-[itex]\frac{8r^3}{7R^3}[/itex])
Redo that one.

(FYI: I agree with the book's answer.)
 
how do you get
radiator0505 said:
ρ = −6q7πR3
 
Doc Al said:
What's the definition of charge density?
i don't really understand charge density. all i know is that it have 3 charge densities, volume, area, and linear.
i just learned this today and i get ρ = −6q/πR3 not ρ = −6q/7πR3.
can you help me solve this step by step?
 
jilia said:
i don't really understand charge density. all i know is that it have 3 charge densities, volume, area, and linear.
Here we are talking about ρ, which is a volume density.

jilia said:
i just learned this today and i get ρ = −6q/πR3 not ρ = −6q/7πR3.
can you help me solve this step by step?
Why don't you show how you arrived at your answer?