Solving General Arithmatic: A^{n}(B+C)^{n} = (AB+AC)^{n}

Titans86 · Jan 25, 2009

Can I make this general statement?

[tex]A^{n}(B+C)^{n} = (AB+AC)^{n}[/tex]?

jgens · Jan 25, 2009

You're comfortable that (ab)^n = (a^n)(b^n) (aside from a few restrictions) correct? Is there anything you can do to change your expression into the form (a^n)(b^n)?

Dick · Jan 25, 2009

Titans86 said:

Can I make this general statement?

[tex]A^{n}(B+C)^{n} = (AB+AC)^{n}[/tex]?

If those are matrices, do you think you might need that A and B+C commute to make that rearrangement?

Titans86 · Jan 25, 2009

not matrices but polynomials...

Dick · Jan 25, 2009

They commute. So you should be fine.

Solving General Arithmatic: A^{n}(B+C)^{n} = (AB+AC)^{n}

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Solving General Arithmatic: A^{n}(B+C)^{n} = (AB+AC)^{n}

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