Solving Harmonic Motion: Need Help Finding System's Energy

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Homework Help Overview

The discussion centers around a problem related to harmonic motion involving a toy car attached to a spring. The original poster seeks assistance in determining the system's energy after being pulled away from the wall and released.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to find the system's energy by calculating the equilibrium point and relating kinetic and potential energy. Some participants explore the relationship between amplitude and energy, while others question how to find the distances where the energies of the car and spring are equal.

Discussion Status

Some participants have provided insights and hints regarding the energy calculations and the relationship between the energies of the spring and the mass. There are indications of multiple interpretations being explored, particularly regarding the graphical representation of energy functions.

Contextual Notes

The original poster expresses uncertainty about the overall energy of the mass-spring system and the method to find the distances where energies are equal. There is mention of specific values and calculations, but no consensus has been reached on the final approach.

fara0815
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Hello there!
I started a new chapter in my script and have done some problems about harmonic motion. After searching in this forum for a similar problem for ages but without any succees, I need to ask you guys to help me out.

Here it is:

A toy car of mass 1kg is attached with a spring to a wall. The spring's constant is 20 N/m. The car is beeing pulled 1 m (horizontal) away from the wall and then let go. It is going back towards the wall up to a distance of 0.4 m.
What is the system's energy?
Every way I took led me into a death end. The most logical way to me is to find first the equilibrium point of the spring which is supposed to be at the same spot where the velocity is the greatest:

[tex]V_{max}= A\times \omega[/tex]

I use 0.6 m for A and I compute omega with

[tex]\omega=\sqrt{\frac{k}{m}}= 0.6m\sqrt{20}= 2.68 m/s[/tex]

The equilibrium point is where KE and KP are equal:

[tex]\frac{1}{2}mv^2=\frac{1}{2}kx^2[/tex]

that gives me the x= 0.366 m.

My guess is that the equilibrium point is 1m - 0.366m.

From here I do not have any clue how to get the over all energy of the mass-spring system.

I would be very happ about any kind of help !
 
Last edited:
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Sometimes it is easier than it seems!
I just figured that A is half of the distance between the two spots (1m and 0.4 m). The equation for the energy of a mass-spring distance is:

[tex]K=\frac{1}{2}kA^2=0.9 Joules[/tex] and that matches with the answer in my script!
Time to go to sleep now ...
 
We all love that eureka moment :smile:
 
we certainly do ;)
Coudl someone give me a hint how to find the distances to the wall where the car and the spring have the same energy?

I know that if I draw the graph for the spring's energy (1/2*k*s^2) and the one for the mass's energy (1/2*m*(A*w*sin(wt))^2) into a diagramm, they probably meet and where they intersect is where the energy is equal, right? Unfortunately, I cannot the a way to do that with math :(
 
and here was that eureka moment again!
the one graph is actually a cos function and the other one is a sin function. In the end, they intersect at pi/4!
 

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