Solving Harmonic Pendulum Homework

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SUMMARY

The discussion focuses on solving the harmonic pendulum problem involving a solid uniform sphere of mass M and radius R attached to a thin uniform rod of mass m and length L. The key equations used include torque τ = Iα and the differential equation for small oscillations, which simplifies to (I_total) d²θ/dt² = τ. Participants emphasize the importance of calculating the moment of inertia using the parallel axis theorem and simplifying the terms to match the simple harmonic motion (SHM) equation to determine the period of oscillation.

PREREQUISITES
  • Understanding of torque and angular acceleration (τ = Iα)
  • Familiarity with the parallel axis theorem for moment of inertia calculations
  • Knowledge of differential equations and their application in physics
  • Concept of small angle approximation in oscillatory motion
NEXT STEPS
  • Calculate the moment of inertia for the pendulum system using the parallel axis theorem
  • Derive the differential equation for small oscillations of the pendulum
  • Simplify the differential equation to match the standard form of simple harmonic motion
  • Research the relationship between angular displacement and period in SHM
USEFUL FOR

Physics students, educators, and anyone studying dynamics and oscillatory motion, particularly in the context of pendulum systems.

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Homework Statement




A pendulum consists of a solid, uniform sphere of mass M and radius
R attached to one end of a thin, uniform rod of mass m and length L.
The pendulum swings freely about the other end of the rod. Find the
period of small oscillations of this pendulum.


Homework Equations





The Attempt at a Solution



T = -mhgsinQ = Ia = Id2Q/dt2

d2Q/dt2 +mghsinQ/I = 0

does sinQ = Q for small approx

should i also be able to find the actual I
 

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joemama69 said:

Homework Statement




A pendulum consists of a solid, uniform sphere of mass M and radius
R attached to one end of a thin, uniform rod of mass m and length L.
The pendulum swings freely about the other end of the rod. Find the
period of small oscillations of this pendulum.

It almost seems from the way the problem is worded that you are expected to use

[tex]\tau = I \alpha[/tex]

where tau is the torque, I is the moment of inertia, and alpha is the angular acceleration. Once you have set up the differential equation that goes with this, you can pick off what you need to answer the question.

Assuming that is the case, the torque is the force (due to gravity) times the distance from the center of mass of the ball to the pivot point, plus the force acting on the center of mass of the rod times the distance between the center of mass of the rod to the pivot point:

[tex]Mg sin(\theta) (R+L) + mg sin(\theta) (\frac{L}{2})[/tex]


The moment of inertia for the system is the sum of the moment of inertia of the ball about the distant pivot point (use the parallel axis theorem) plus the moment of inertia of the rod about the end point (pivot point). I'll let you figure that out. (One of those two moments of inertia you can look up.)

Then your differential equation is:

[tex](I_{total}) \frac{d^2 \theta} {d^2 t} = \tau[/tex]


One of your tasks will be to simplify the terms for I total and the torque into something neater. Since it's a small angle oscillation, replace the sines with just the angle. Simplify the way the equation looks and try to make it match the equation for simple harmonic motion. Check and see what terms in the D.E. for SHM determine the period, and figure out your answer.
 

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