Solving Heat Capacity Problem: 60K to 80K

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SUMMARY

The discussion focuses on calculating the entropy change for a liquid with a temperature-dependent heat capacity, defined as Cp = 20 J K−1 + T × 0.5 J K−2, when heated from 60 K to 80 K. The relevant equation for this calculation is C = q/ΔT, where q represents the heat added. To find the total entropy change, integration of the heat capacity over the specified temperature range is necessary, addressing the confusion regarding the application of the temperature-dependent heat capacity in this context.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically heat capacity.
  • Familiarity with integration techniques in calculus.
  • Knowledge of the relationship between heat (q), temperature change (ΔT), and entropy.
  • Experience with temperature-dependent functions in physical chemistry.
NEXT STEPS
  • Study the integration of heat capacity functions to calculate entropy changes.
  • Learn about the first law of thermodynamics and its application in heat transfer problems.
  • Explore examples of temperature-dependent heat capacities in various materials.
  • Review the concept of entropy and its significance in thermodynamic processes.
USEFUL FOR

Students in thermodynamics, physicists, and engineers dealing with heat transfer and entropy calculations in materials science.

Pete_01
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Homework Statement



In the temperature range from 60 K to 80 K, a certain amount of liquid has a
temperature dependent heat capacity that is given by Cp = 20 J K−1 + T × 0.5 J K−2.
Determine the entropy change resulting from heating this sample from 60 K to 80 K.


Homework Equations


C=q/deltaT



The Attempt at a Solution



This one is confusing me. How does the temperature dependent heat capacity fit in, when the temperature is a range (60-80k)? Also, what equation should I use?
 
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I guess you should integrate.
 

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