Solving Homework Equations for Relativistic Rocket

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SUMMARY

The discussion focuses on solving homework equations related to the physics of relativistic rockets, specifically analyzing the final speed of a rocket after fuel ejection. The derived formula for a non-relativistic rocket is vf = v0 ln(1 + M/m). For a relativistic rocket utilizing matter/antimatter fuel, the final speed is expressed as 1 + M/m = [(c + vf)/(c - vf)]^0.5. The attempt at a solution involves momentum conservation and energy equations, with particular emphasis on the energy of emitted photons and their relationship to the rocket's momentum.

PREREQUISITES
  • Understanding of relativistic physics concepts, including gamma factor (γ).
  • Familiarity with momentum conservation principles in physics.
  • Knowledge of energy-momentum relations, particularly for photons.
  • Basic calculus for handling differential equations in physics.
NEXT STEPS
  • Study the derivation of the gamma factor (γ) in special relativity.
  • Learn about the conservation of momentum in relativistic contexts.
  • Explore the energy-momentum relation for photons in detail.
  • Investigate the implications of matter/antimatter reactions in propulsion systems.
USEFUL FOR

Students of physics, particularly those studying special relativity and rocket propulsion, as well as educators looking for examples of relativistic equations in practical applications.

joker_900
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Homework Statement




I've done the first part, I'm just posting it for completeness

A rocket at rest in deep space has a body of mass m and carries an initial mass
M of fuel, which is ejected at non-relativistic speed v0 relative to the rocket. Show that
the speed of the rocket vf after all the fuel is ejected is given by

vf = v0 ln(1 + M/m)

Now consider the case of a relativistic rocket, where matter/antimatter fuel is
annihilated and expelled from the rocket as photons. Show that the final speed of this
rocket is given by

1 + M/m = [(c + vf)/(c - vf)]^0.5

Homework Equations





The Attempt at a Solution



So for the second bit: I called the mass at any instant n, and attempted to conserve momentum:

y1(n + &n)v = y2(v + &v)n - p

Where y1 is the gamme for the velocity before the emission of a small fuel element &n (the & is supposed to be a delta), and y2 is the gamme for the velocity of the rocket after emission.

y1(n - dn)v = y2(v + dv)n - E

Where E is the energy of the emitted photon(s). Here's where I get stuck. Is E = &nc^2 or E = y1 &nc^2 or something else?
 
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Consider the initial and final states only.

Let E and p be the magnitudes of the total energy and total momentum of the photons respectively. (It does not matter that the photons have been emitted at different times, since all of the travel at the same speed c anyway.) Let g denote gamma(v).

E = pc (for photons).

P = mgv, since the magnitude of the final momentum of the rocket must be equal to that of the photons.

Now use the fact that the initial energy must be equal to the final energy of the rocket and the photons.
 

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