Solving Ideal Gas Problem Homework: Final Pressure of Tank w/ Vapor & Water

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SUMMARY

The discussion centers on calculating the final pressure of a closed tank containing vapor and water, given specific parameters: an initial pressure of 1 bar, a water mass of 400,000 kg, and an initial volume of 80,000 m³. The user initially calculated the final pressure as 0.167 bar but later proposed that the final pressure should be 6 bar based on the volume ratio of 480,000 m³ to 80,000 m³. The confusion arises from the misunderstanding of how volume changes affect pressure in a fixed tank scenario, emphasizing the need for clarity on the ideal gas law principles.

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Homework Statement


Calculate the final pressure of the closed tank containing vaper if it is filled with a water.If the water mass is 400,000 kg is injected into the tank, initial tank pressure is 1bar and the volume is 80,000m^3, density of the vapor 1 kg/m^3 at 1 bar, treat the air and water as ideal gases.


Homework Equations





The Attempt at a Solution


Volume before V1=80,000m^3
Volume after V2=480,000m^3
initial pressure = 1 bar

final pressure is going to be 0.167 bar, but the question is asking me that with the same tank how much the pressure is going to be and in this case my answer is wrong!

as the volume increase it is normal that the pressure will decrease but if we have a fixed tank!

I really confused!
 
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I think something ring in my head!

Since the initial volume is before V1=80,000m^3
Volume after V2=480,000m^3

if we take the ratio of it V2/V1= 6 in this case the pressure for the same tank is going to be 6 bar! is it true
 
I need a help please
 

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