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JasonHathaway
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Homework Statement
A tank has a saturated liquid at 0.2 MPa. An amount of heat is transferred until the pressure in the tank became 0.1 MPa. If the volume of the tank 1 m3. Determine:
1- The final state of the water
2- The mass of the vapor in the tank
3- The work
4- The process on P-v diagram
Homework Equations
V=C (Volume is constatnt)
m (mass) = Volume (V) / Specific volume (v)
The Attempt at a Solution
v1=vf |P=0.2 MPa = 0.8857 m3/kgv1= v2=0.8857 m3/kg
At P1=0.1 MPa, v2=0.8857 m3/kg: vf < v2 < vg
The water is mixture of saturated liquid and saturated vapor --> The final state of the water
m=V/v = (1/0.8857) = 1.13 kg --> The mass of the vapor in the tankWork is zero since the volume is constant --> The work
P-v diagram: http://i.imgur.com/Kz0cVVP.jpg