Solving Implicit Functions: x(u^2)+v=y^3, 2yu-x(v^3)=4x

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SUMMARY

The discussion focuses on solving the implicit functions defined by the equations x(u^2) + v = y^3 and 2yu - x(v^3) = 4x. The correct derivatives are established as a) du/dx = ((v^3) - 3x(u^2)(v^2) + 4) / (6(x^2) - u(v^2) + 2y) and b) dv/dx = (2x(u^2) + 3(y^3)) / (3(x^2)u(v^2) + y). The approach involves implicit differentiation of both equations to derive the expressions for du/dx and dv/dx, confirming that u and v are indeed functions of x and y.

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Homework Statement



If x(u^2) + v=(y^3), 2yu - x(v^3)=4x. Find a) du/dx and b) dv/dx

Homework Equations





The Attempt at a Solution



Not sure if I am supposed to differentiate as is, or try and write u and v as functions of x and y. The answer is supposed to be:

a) ((v^3)-3x(u^2)(v^2)+4)/(6(x^2)-u(v^2)+2y)

b) (2x(u^2)+3(y^3))/(3(x^2)u(v^2)+y)
 
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so i assume v & u are both functions of x & y? ie u=u(x,y), v=v(x,y)

i would attempt to implicitly differentiate both equations, which will give you 2 eqns containing du/dx and dv/dx, then use them to solve for each
 

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