Solving Inequality with x=2y - Answers & Theories

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Homework Help Overview

The discussion revolves around solving a system of equations and inequalities involving the variables x and y, specifically the equations x=2y and the inequality 5x

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the conditions under which the equality and inequality can coexist, with some questioning the correctness of the proposed solution set. There are attempts to clarify how the inequality defines a region in relation to the line defined by the equality.

Discussion Status

There is an ongoing exploration of the relationship between the equations and the inequalities, with some participants suggesting that the original interpretation of the solution set may be incorrect. The conversation is productive, with various interpretations being examined.

Contextual Notes

Some participants express concern about the implications of the proposed solution set, indicating that the conditions may not be satisfied by all points in the defined quadrant. There is a focus on the specific relationship between x and y as dictated by the equality.

Mindscrape
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So I was helping my gf go over some GRE math questions, and we came across a strange question.

Solve for x and y
x=2y
5x<y+7

I said that the answer would be

y<7/9 and x<14/9

this is the right answer, but she asked how that works. How do both the equality and inequality hold true at the same time? Shouldn't the answer be undetermined? I don't quite know how to answer the question. My opinion is that as long as both x and y are less than their respective inequality, then the equality will then hold.

Are there any more precise thoughts or theories regarding the subject?
 
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If that is the right answer, it simply means that x and y have to simultaneously satisfy the conditions that y<7/ and x<14/9 and x=2y. So in other words, x = -5 and y = -3 would not satisfy the equation but x = -5 and y = -2.5 will. Your idea is a bit backwards, the equality holding is a much stronger condition but in the end, one condition being being true doesn't mean other is true
 
Last edited:
The inequality 5x<y+7 corresponds to the half plane above the line y=5x-7. The solutions correspond to the portion of the line x=2y that lies in that half plane.
 
Since x= 2y, the second inequality becomes 5(2y)< y+ 7. 10y< y+ 7 so 9y< 7, y< 7/9.

I would be inclined to say that "y< 7/9, x< 14/9" is NOT the correct answer because that implies that any point (x, y) in the quadrant of R2 satisfying x< 14/9, y< 7/9, satisfies those. That is not the case. The correct answer is "y< 7/9, x= 2y". That is, the solution set is the ray x= 2y for all y< 7/9.
 
HallsofIvy said:
Since x= 2y, the second inequality becomes 5(2y)< y+ 7. 10y< y+ 7 so 9y< 7, y< 7/9.

I would be inclined to say that "y< 7/9, x< 14/9" is NOT the correct answer because that implies that any point (x, y) in the quadrant of R2 satisfying x< 14/9, y< 7/9, satisfies those. That is not the case. The correct answer is "y< 7/9, x= 2y". That is, the solution set is the ray x= 2y for all y< 7/9.

Ah yes, that sounds better to me too. Even though that's not a possible answer, it makes better mathematical sense, and I agree that it should in fact be the ray x= 2y for all y< 7/9.
 

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