Solving Inertia of a Record Homework

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SUMMARY

The discussion centers on calculating the moment of inertia of a record dropped onto a rotating turntable with a known moment of inertia of 5.2 kgm² and an initial angular velocity of 36 rpm. After the record is dropped, the combined system rotates at 33 rpm. The relevant equations involve the conservation of angular momentum and rotational kinetic energy, specifically using the initial and final angular velocities of the system, which are expressed in radians per second as ω₁ = 6π/5 rad/s and ω₂ = 11π/10 rad/s. The solution requires applying these principles to find the moment of inertia of the record.

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  • Understanding of rotational dynamics and angular momentum conservation
  • Familiarity with the concept of moment of inertia
  • Knowledge of rotational kinetic energy equations
  • Ability to convert between revolutions per minute (rpm) and radians per second
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  • Learn how to calculate moment of inertia for various shapes
  • Explore the relationship between rotational kinetic energy and angular velocity
  • Practice problems involving combined rotational systems and energy conservation
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Homework Statement


A turntable for playing records has a moment of inertia of 5.2 kgm^2 and is rotating with an angular velocity of 36 rpm. A record, initially at rest is dropped straight down onto the rotating turntable. The record and turntable rotate together at 33 rpm. Find the moment of the inertia of the record.




Homework Equations


[tex]\omega_{i} = \frac{6\pi}{5} \frac{rad}{sec}[/tex]
[tex]\omega_{f} = \frac{11\pi}{10} \frac{rad}{sec}[/tex]


The Attempt at a Solution


I really don't have a clue about how to solve this. It's a problem on a practice exam, not homework. I thought I could solve it with torque, but then there is no coefficient of friction to calculate force.
The only thing I can think to do is to calculate the difference in kinetic energy but that didn't give me the right answer.
If someone could give me some direction that would be amazing. Thanks.
 
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Rotational Kinetic Energy looks to be the key.

You have something rotating with a known I*ω2/2

And you are given a modified I*ω2/2 (the added mass of the record - distributed in the same manner as the turntable)
that yields a new I*ω2/2 where they give you the new ω.
 

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