Solving Initial Value Problems for Second Order Differential Equations

  • Thread starter Thread starter tracedinair
  • Start date Start date
  • Tags Tags
    Initial Value
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
tracedinair
Messages
47
Reaction score
0

Homework Statement



Solve the following IVPs.

a) y'' + y = 0 for y(x0)=1 and y'(x0)=0

b) y'' - λ2y = 0 for y(x0)=0 and y'(x0)=1

Homework Equations


The Attempt at a Solution



a) Two distinct solutions for y'' + y = 0 are cos(x) and sin(x).

So, y(x0) = C1cos(x0) + C2sin(x0) = 1

y'(x0) = -C1sin(x0) + C2cos(x0) = 0

b) Two distinct solutions for y'' + λ2y = 0 is just e^([tex]\lambda[/tex]x) and e^(-[tex]\lambda[/tex]x)

So,

y(x0) = C1e^([tex]\lambda[/tex]x0) + C2e^([tex]\lambda[/tex]x0)) = 0

y'(x0) = C1λe^([tex]\lambda[/tex]x0) - C2λe^(-[tex]\lambda[/tex]x0) = 1

Now do I need to go through and solve for the C's or I am OK?
 
Physics news on Phys.org
tiny-tim said:
Yup! :biggrin:

Thank you, my notes weren't very clear on the next step.