Solving Integration Problem: Get Expert Advice

  • Context: Undergrad 
  • Thread starter Thread starter birdhen
  • Start date Start date
  • Tags Tags
    Integration
Click For Summary
SUMMARY

The discussion centers on solving the integral equation Ht=∫(da/√((1-ω)*a^-1+(ω*a^-2)). Participants suggest a method to simplify the integral by multiplying the numerator and denominator by 'a' to eliminate the inverse terms, followed by completing the square to facilitate further simplification. This approach is aimed at transforming the integral into a more manageable form for evaluation.

PREREQUISITES
  • Understanding of integral calculus, specifically techniques for solving integrals.
  • Familiarity with algebraic manipulation, including completing the square.
  • Knowledge of mathematical notation, particularly integrals and square roots.
  • Basic understanding of the variable 'ω' and its role in the equation.
NEXT STEPS
  • Research techniques for simplifying integrals involving square roots.
  • Learn about completing the square in algebraic expressions.
  • Explore advanced integral calculus methods, such as substitution and integration by parts.
  • Study the properties and applications of the variable 'ω' in mathematical contexts.
USEFUL FOR

Mathematics students, educators, and anyone involved in calculus who seeks to enhance their problem-solving skills related to integral equations.

birdhen
Messages
31
Reaction score
0
I am having problems trying to solve the following problem and wondered if anyone could point me in the right direction..

Ht=integral of:(((1-omega)*a^-1+(omega*a^-2))^-1/2)da

cheers
 
Physics news on Phys.org
Welcome to PF!

birdhen said:
I am having problems trying to solve the following problem and wondered if anyone could point me in the right direction..

Ht=∫(da/√((1- ω)*a-1+(ω*a-2))

cheers

Hi birdhen! Welcome to PF! :smile:

(have an integral: ∫ and a square-root: √ and an omega: ω :smile:)

Hint: multiply top and bottom by a (to get rid of the nasty inverses :frown:), and then complete the square …

in other words, put the bracket into the form something2 ± a constant. :smile:
 
thank you!
 

Similar threads

  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K