Solving Inverse Trig Function: sin-1(1/sqrt2) Without a Calculator

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Homework Help Overview

The discussion revolves around finding the exact value of the expression sin-1(1/√2) in degrees without using a calculator or table. Participants are exploring the context of inverse trigonometric functions and their relationship to the unit circle and right triangles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the inverse sine function and the corresponding angle in a right triangle. There are attempts to visualize the problem using the Pythagorean theorem and to relate it to known angles.

Discussion Status

The conversation is ongoing, with participants sharing their thoughts and attempts to understand the problem. Some guidance has been offered regarding the relationship between the sine function and angles, but there is no explicit consensus on the final resolution of the problem.

Contextual Notes

Participants note that their previous experience has mainly involved the unit circle and calculators, which may limit their approach to this problem. There are also references to related questions involving sec(arcsin(1/√2)), indicating a broader exploration of inverse trigonometric functions.

MacLaddy
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Homework Statement



Find the exact value of this expression in degrees without using a calculator or table.

sin-1(1/sqrt2)



Homework Equations



Typical inverse function



The Attempt at a Solution



I can figure this out easily on my calculator, as it comes to 45 degrees, but how could I figure this out without one? It isn't on the unit circle.
 
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MacLaddy said:

Homework Statement



Find the exact value of this expression in degrees without using a calculator or table.

sin-1(1/sqrt2)



Homework Equations



Typical inverse function



The Attempt at a Solution



I can figure this out easily on my calculator, as it comes to 45 degrees, but how could I figure this out without one? It isn't on the unit circle.

Let y = sin-1(1/sqrt(2)). Then sin(y) = sin(sin-1(1/sqrt(2))) = 1/sqrt(2).

Can you figure it out from there?
 
No, I think I can follow you that far, and I can see that corresponds with a triangle and the Pythagorean theorem if I draw it out, but I am still not seeing how to end at 45 degrees.

EDIT* Oh, I may see. So I multiply everything on the triangle by the square root of 2, and that gives me sqrt2/2?
 
So far in my class we have been dealing mainly with either the unit circle, or a calculator. A few random identities in between, but nothing quite like this.

I have one more follow up question to that one, if I may, and it's because I think it's relevant to how the one above was completed. (if I did in fact figure that out correctly) The question below goes like this.

Find the exact value of each composition without using a calculator or table.

sec(arcsin(1/sqrt2)).

Trying this I can not find an exact value, other than sec(45deg), or 1/cos(45deg)
 
MacLaddy said:
Trying this I can not find an exact value, other than sec(45deg), or 1/cos(45deg)

You're right there. what is cos(45)? And what is the value of that 1/cos(45)
 
Blu3eyes said:
You're right there. what is cos(45)? And what is the value of that 1/cos(45)

Ugh, 2sqrt2/2. I must need sleep. Thanks Blu3eyes and Mark44. I appreciate it. Couldn't see the forest through the trees on that one.
 

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