Solving Isomorphic Rings: \mathbb{F}_5[x]/(x^2+2) & \mathbb{F}_5[x]/(x^2+3)

  • Context: Graduate 
  • Thread starter Thread starter JackTheLad
  • Start date Start date
  • Tags Tags
    Rings
Click For Summary
SUMMARY

The discussion focuses on demonstrating the isomorphism between the rings \(\mathbb{F}_5[x]/(x^2+2)\) and \(\mathbb{F}_5[x]/(x^2+3)\). The key approach involves finding a homomorphism \(\phi:R\to S\) that is linear and satisfies \(\phi(1)=1\). The proposed mapping \(x \mapsto 2x\) is evaluated, leading to the conclusion that both rings are generated by adjoining a root of an irreducible quadratic to a field of order 5, confirming their isomorphic nature. An explicit isomorphism must be provided as part of the solution process.

PREREQUISITES
  • Understanding of ring theory and homomorphisms
  • Familiarity with finite fields, specifically \(\mathbb{F}_5\)
  • Knowledge of polynomial rings and irreducible polynomials
  • Ability to perform algebraic manipulations within modular arithmetic
NEXT STEPS
  • Study the properties of finite fields and their isomorphisms
  • Learn how to construct explicit ring homomorphisms
  • Explore the concept of irreducible polynomials over finite fields
  • Investigate the structure of polynomial rings modulo irreducible polynomials
USEFUL FOR

Mathematicians, particularly those specializing in abstract algebra, students studying ring theory, and anyone interested in the properties of finite fields and their applications in algebra.

JackTheLad
Messages
7
Reaction score
0
Hi guys,

I'm trying to show that \mathbb{F}_5[x]/(x^2+2) and \mathbb{F}_5[x]/(x^2+3) are isomorphic as rings.

As I understand it, I have to find the homomorphism \phi:R\to S which is linear and that \phi(1)=1.

I'm just struggling to find what I need to send x to in order to get this work.
 
Physics news on Phys.org
Well, what property must the image of x satisfy?


If all else fails, there aren't many possibilities, you could just try them all.
 
Actually, I think x --> 2x might do it, because

x^2 + 2 \equiv 0
(2x)^2 + 2 \equiv 0
4x^2 + 2 \equiv 0
4(x^2 + 3) \equiv 0
x^2 + 3 \equiv 0

Is that all that's required?
 
Do you have to provide an explicit isomorphism? If not you can just use the fact that finite fields with the same cardinality are isomorphic...both of these fields are generated by adjoining a root of an irreducible quadratic to a field of order 5, and hence both have 25 elements.
 
Yeah, unfortunately I do have to show the explicit isomorphism (we're supposed to do it 'the long way')
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 21 ·
Replies
21
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 26 ·
Replies
26
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K