Solving Kinetics Questions: Two Cars Traveling on a Highway

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Homework Help Overview

The problem involves two cars traveling on a highway at different constant speeds, specifically 55 mi/h and 65 mi/h. The questions focus on determining the time difference in arrival at a 10-mile destination and the distance required for the faster car to have a 15-minute lead over the slower car.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss calculating the time difference for part (a) and explore how to set up equations for part (b). There is a focus on the relationship between speed, distance, and time.

Discussion Status

Some participants have confirmed the approach for part (a) and are considering how to apply similar reasoning to part (b). There is an indication that guidance has been provided regarding the relevant equations and the relationship between the distances and time leads.

Contextual Notes

Participants express uncertainty about setting up equations and the specific requirements for part (b). There is a mention of needing to relate the distance for part (b) to the time lead established in part (a).

aquapod17
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Homework Statement


Two cars travel in the same direction along a straight highway, one at a constant speed of 55 mi/h and the other at 65 mi/h.

(a) Assuming that they start at the same point, how much sooner does the faster car arrive at a destination 10 mi away?
______ min
(b) How far must the faster car travel before it has a 15-min lead on the slower car?
______ mi


Homework Equations


I'm not sure how to set up an equation.


The Attempt at a Solution


I divided 10 mi by each speed, then multiplied each result by 60 and compared minutes.
 
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For part a you seem to have started off correctly. All you need to do is find the difference in arrival times.

Any ideas for part b?
 
Welcome to PF, aquapod17.

You did part (a) correctly. The relevant equation is the one that relates speed, distance, and time to each other. (You must have been told this equation, or it's in your textbook ... otherwise you would not be asked to do a problem like this.)

(b) Instead of 10 miles, what would the distance be so that your answer is 15 minutes? You already know, from part (a), if that distance is greater than or less than 10 miles.
 
Thanks I got it!
 

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