Finding a second velocity with a first and average velocity

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Homework Help Overview

The problem involves a car traveling at two different constant speeds over equal distances, with the goal of finding the second speed given the average speed for the entire trip. The context is kinematics, specifically focusing on average velocity calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of average velocity equations, with some suggesting a weighted average approach instead of a simple mean. There are questions about how to handle multiple unknowns when applying this method.

Discussion Status

Some participants have offered guidance on using the correct equation for average velocity, while others are exploring how to express the relationship between distance, time, and speed. There is an ongoing exploration of different methods to approach the problem.

Contextual Notes

Participants note the absence of specific values for time and distance, which complicates the application of standard equations. The original poster expresses frustration with the provided equations not being helpful in reaching the expected answer.

Heidi

Homework Statement


A car travels along a straight line at a constant speed of 44.5 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 28.5 mi/h. NOTE: this is a practice problem.

Homework Equations


V_avg=(V_i+V_f)/2

The Attempt at a Solution


28.5=44.5/2+V_f/2
28.5*2-44.5=V_f
V_f=12.5 mi/h
This is not correct because the answer sheet says that the answer is 21 mi/h. I have been trying different ways including a proportionality using distance and time, but I cannot seem to get 21 as any of my answers. I feel as if none of the equations I have been given help with this problem because there is no acceleration or exact time and exact distance.
 
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Try using a weighted average as your relevant equation, rather than the mean of the velocities, which assumes an equal time traveled at each velocity.
 
MarkFL said:
Try using a weighted average as your relevant equation, rather than the mean of the velocities, which assumes an equal time traveled at each velocity.
How might I go about doing that then? It would give me two unknowns instead of just one.
 
Heidi said:
How might I go about doing that then? It would give me two unknowns instead of just one.

I would begin by stating:

##\displaystyle\overline{v}=\frac{v_1t_1+v_2t_2}{t_1+t_2}##

Now, you are given ##\overline{v}## and using the relation ##d=vt##, can you express the RHS in terms of everything else given, as well as the unknown velocity?
 
Your expression for the average velocity (or more correctly speed in this case) is total distance traveled divided by total time required to travel that distance.
 
MarkFL said:
I would begin by stating:

##\displaystyle\overline{v}=\frac{v_1t_1+v_2t_2}{t_1+t_2}##

Now, you are given ##\overline{v}## and using the relation ##d=vt##, can you express the RHS in terms of everything else given, as well as the unknown velocity?
MarkFL said:
I would begin by stating:

##\displaystyle\overline{v}=\frac{v_1t_1+v_2t_2}{t_1+t_2}##

Now, you are given ##\overline{v}## and using the relation ##d=vt##, can you express the RHS in terms of everything else given, as well as the unknown velocity?
I finally got it figured out. I was supposed to use the distance/speed formula. Thank you for your help anyway!
 

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