Calculating for a distance including vi, vf, time, and Ff

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varoney
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Homework Statement


For a project we have to find a movie scene and calculate using any variables we can find. I am using Back to the Future and want to calculate the distance the DeLorean travels in one of the first scenes when they're first using it. I'd also like to find the acceleration from the same scene.

Homework Equations


I know:
t= 12.35s (From the time the car begins to move to when it reaches 88 mi/h)
d=? a=?
vi= 28.07411 m/s (The speed the car reaches when he releases it)
vf= 39.3395 m/s
μ= 0.72 (car tires on asphalt)
m=1,230 kg
I think I calculated properly for Ff as well which comes to 8687.736 N

The Attempt at a Solution


I have calculated separately for distance and for friction but I don't know if my friction calculation is correct or how to apply the number to the calculation for distance.
 
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varoney said:

Homework Statement


For a project we have to find a movie scene and calculate using any variables we can find. I am using Back to the Future and want to calculate the distance the DeLorean travels in one of the first scenes when they're first using it. I'd also like to find the acceleration from the same scene.

Homework Equations


I know:
t= 12.35s (From the time the car begins to move to when it reaches 88 mi/h)
d=? a=?
vi= 28.07411 m/s (The speed the car reaches when he releases it)
vf= 39.3395 m/s
μ= 0.72 (car tires on asphalt)
m=1,230 kg
I think I calculated properly for Ff as well which comes to 8687.736 N

The Attempt at a Solution


I have calculated separately for distance and for friction but I don't know if my friction calculation is correct or how to apply the number to the calculation for distance.
Here V(f), V(i) and time are given, by these data you can simply calcute net acceleration which is equal to acceleration provided by engine to car minus acceleration provide by frictional force.so there is no need to consider this number in calculation of distance