Solving Laplace's Equation Homework Statement

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    Laplace's equation
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Homework Help Overview

The discussion revolves around solving Laplace's equation, particularly in the context of potential functions and boundary conditions. Participants explore the implications of the equation in both one-dimensional and two-dimensional scenarios, as well as the application of image charges in electrostatics.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to solve the Laplace equation for a potential function within specified bounds and expresses uncertainty about the integration process. Some participants question the dimensionality of the problem and the correctness of the equation setup, while others suggest reviewing simpler cases to build understanding.

Discussion Status

The discussion is active, with participants providing guidance on foundational concepts and questioning assumptions. There is a mix of interpretations regarding the dimensionality of the problem, and some participants are exploring the use of image charges in relation to boundary conditions.

Contextual Notes

Participants note potential confusion regarding the application of Laplace's equation in different dimensions and the specific boundary conditions related to the problem involving conducting plates and a point charge.

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Homework Statement


I have a really dumb question, but I want to make sure this is right...
So I have the integral (d2V)/(dф2) = 0. I am solving for the potential function on the bounds, 0 < ф < фo. I will also be solving on range of фo < ф < 2∏.


Homework Equations


The Laplace equation is above.


The Attempt at a Solution


So, I am just having my doubts... When solving for 0 < ф < фo, I take the first integral with respect to d/dф, and after this I get dV/dф = arbitrary constant. If I take another integral on this (after multiplying both sides by dф), I get V = фo*arbitrary constant, right?!?

When solving for the other bounds, фo < ф < 2∏, I get V = arbitrary constant*(2∏ - фo), yes?!

Thank you for all help, I apologize for the silly question. I just wanted to make sure...
 
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If you mean in one dimension is a solution to Laplace's equation a linear function, a*phi+b. Yes, it is. On the other hand, if you are working in two dimensions and phi is an angular coordinate, then you've got the Laplace equation wrong. It has to involve the other coordinate as well.
 
Q: Consider a system consisting of a pair of earthed conducting plates at right angles to each other, one at the z=0 and the other in the y=0 plane and a positive point charge Q at (0,1,2). Show that Laplace's equation (with appropriate boundary conditions) can be solved for this system by replacing the conducting plates with a family of image charges.

I really don't know where to start, it'd be great if someone could help please.
 
Start by reviewing how to do it with one plate and why it works. Two plates isn't that much harder.
 

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