Solving Laplacian in Ex(r,z) Equation

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The discussion focuses on solving the Laplacian in the context of the equation Ex(r,z) = Eo*e[-(r/ro)2]*e[-ibz]. Participants clarify that the Laplacian operator (∇²) should be applied to Ex rather than Eo. They emphasize the importance of maintaining consistency in coordinate systems, suggesting the use of cylindrical coordinates for the Laplacian, which includes terms for both radial and axial derivatives.

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I need to know the steps involved in solving this laplacian.

Ex(r,z) = Eo*e^[-(r/ro)^2]*e^[-ibz]

the laplacian \/^2*Eo = ?
Eo is a vector
\/ is laplacian symbol

any help would be appreciated.

Thanks in advance.
 
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you probably meant \/^2*Ex, not \/^2*Eo.

Well, the problem is that there are polar and cartesian coordinates mixed up in the expression of Ex. So either transform r in cartesian and use the cartesian laplacian or transform z in polar and use the polar laplacian.
 
No, that's in "cylindrical coordinates" which is perfectly fine- just use polar coordinates with z appended.

The Laplacian of Y in cylindrical coordinates is
[tex]\frac{\partial^2 Y}{\partial r^2}+ \frac{1}{r}\frac{\partial Y}{\partial r}+ \frac{1}{r^2}\frac{\partial^2 Y}{\partial \theta^2}+ \frac{\partial^2 Y}{\partial z^2}[/tex]
 
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