MHB Solving Limit Problem: n→∞, n!-1/n³ln(n!)

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The limit of the expression lim(n→∞) (n! - 1)/(n³ ln(n!)) approaches infinity due to the growth rate of n!. The logarithm of n! can be approximated by the sum of logarithms, which is less than or equal to n(n + 1)/2. This indicates that ln(n!) grows significantly slower than n!. The core argument relies on demonstrating that n!/n^m approaches infinity for any positive integer m as n increases. Thus, the limit diverges to infinity.
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Could anyone tell me please why the limit of this guy is infinity?

\lim_{n\to\infty} \frac{n!-1}{n^{3} \ln(n!)}
 
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Lisa91 said:
Could anyone tell me please why the limit of this guy is infinit
\lim_{n\to\infty} \frac{n!-1}{n^{3} \ln(n!)}
See what you can do with this inequality.

$\ln \left( {n!} \right) = \sum\limits_{k = 1}^n {\ln (k)} \leqslant \sum\limits_{k = 1}^n k =\frac{{n(n + 1)}}{2}$
 
The 'core' of the problem is to demonstrate that...

$\displaystyle \lim_{n \rightarrow \infty} \frac{n!}{n^{m}} = \infty$ (1)

... for all integers m>0. That is easily achieved supposing n>m, writing ...

$\displaystyle \frac{n!}{n^{m}}= \frac{n\ (n-1)\ (n-2)\ ...\ (n-m+1)}{n^{m}}\ (n-m)\ (n-m-1)\ ...\ 2 = $

$\displaystyle = 1\ (1- \frac{1}{n})\ (1-\frac{2}{n})\ ... (1-\frac{m-1}{n})\ (n-m)\ (n-m-1)\ ...\ 2$ (1)

... and observing what happens if n tends to infinity...

Kind regards$\chi$ $\sigma$
 
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