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Cantworkit

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**[SOLVED] linear motion**

## Homework Statement

A car enters a turn at 85 km/h, slows to 55 km/h, and emerges 28 s later at 35 degrees to its original motion, still moving at 55 km/h. What is the magnitude an direction of the average acceleration measure with respect to the car's original direction? Book gives the answer as 0.5 m/s^2 and 142 degrees.

## Homework Equations

a=(v2-v1)/delta t

## The Attempt at a Solution

V2x= 55 cos 35 degrees=55(.819)=.45 km/h

V1x=80 km/h

a= 35 km/h (1000m)/28s(3600s)= 0.35 m/s^2

I have no idea how to arrive at the direction of the acceleration vector.