Solving linear systems + gaussian elimination

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Homework Help Overview

The discussion revolves around solving linear systems using Gaussian elimination and exploring the implications of having more variables than equations. Participants are examining specific questions related to the steps involved in reaching reduced row-echelon form and the process of back substitution.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the implications of their findings in the context of infinite solutions due to the system's structure. They express uncertainty about the next steps in their solution process, particularly regarding back substitution.
  • Some participants suggest methods for reaching reduced row-echelon form and discuss how to express variables in terms of others.
  • There is a question raised about a potential mistake in the matrix representation, prompting a review of the entries in the matrix.

Discussion Status

The discussion is active, with participants providing guidance on how to approach the problems. Some have successfully navigated parts of the questions, while others are still seeking clarity on specific steps. There is an acknowledgment of a correction regarding the matrix entries, indicating a collaborative effort to refine the understanding of the problem.

Contextual Notes

Participants note that the system has more variables than equations, which suggests the presence of infinite solutions. There is also a focus on the importance of achieving reduced row-echelon form and the challenges associated with back substitution.

dcramps
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Homework Statement


http://img.rflz.net/problems.jpg

Homework Equations


The Attempt at a Solution


Question 1
x4 = 1 + 4x5
but from there I am not sure where to go or if there is even a solution?

Question 2
I eventually got the matrix down to this:

Code:
1  2 -3  1   4     1
0  1  1  0   1     1
0  0  1  0  -1/3  -1/3
0  0  0  1  -1/3   4/3

but again I am not sure if that is enough? I don't understand how back substitution is possible.

Question 3
Similar to 3. I sort of got it to row-echelon, but am having trouble. Any help on the previous question should help here.

Thanks
 
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For questions 1 and 2 you have more variables than equations, so you're going to have an infinite number of solutions.

For 1, you can get the system to reduced row-echelon form, which is a step beyond Gaussian elimination. In RREF, each row that has a nonzero first entry has 1 in that position, and all rows above and below have 0 in the same position. Doing this, I was able to get the system in this form:
Code:
[1 0 -5 0 36 | 3]
[0 1 1 0 -15 |-3]
[0 0 0 1 -4 | 1]
From this you can write x1 in terms of x3 and x5, x2 in terms of x3 and x5, and x4 in terms of x5.

If you do this by back substitution, you'll start with the 3rd equation, and write x4 in terms of x5. Substitute for x4 in the 2nd equation, so you'll eventually get to x2 in terms of x3 and x5. Substitute what you have here for x2 in the 1st equation to get x1 in terms of x3 and x5. IOW, the same as what I did before using RREF, which is essentially Gauss elimination with back substitution.

For question 2, do the same thing.
 
Thanks for the reply. I managed to get 2 and 3 on my own, but your advice on question 1 should be very useful. :)
 
I tried putting the system in the form you have, and I think you have made a mistake. The -3 in the last column should be a -1, no?
 
Yes, you're right. The last entry in the 2nd row should be -1.
Code:
[1 0 -5 0 36 | 3]
[0 1 1 0 -15 |-1]
[0 0 0 1 -4 | 1]
 

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