How should the radius MP be drawn?

  • Context: Undergrad 
  • Thread starter Thread starter Dafoe
  • Start date Start date
  • Tags Tags
    Radius
Click For Summary
SUMMARY

The discussion focuses on determining how to draw the radius MP in a geometric configuration defined by three semicircular arches, where the smallest arch has a radius denoted as r. The objective is to divide the colored area into two equal parts by finding the optimal position of point P. The proposed method involves quantifying the position of P, calculating the areas of the left and right segments of the blue region, and solving for P without the need for integration. The left area is calculated as one-fourth of the large circle's area plus half of the small circle's area.

PREREQUISITES
  • Understanding of semicircular geometry
  • Knowledge of area calculation for circles and semicircles
  • Familiarity with algebraic equations
  • Basic skills in geometric reasoning
NEXT STEPS
  • Study the properties of semicircles and their areas
  • Learn how to derive equations for area partitioning in geometric shapes
  • Explore geometric optimization techniques
  • Investigate applications of calculus in area calculations, even if not required here
USEFUL FOR

Mathematicians, geometry enthusiasts, students studying calculus and geometry, and anyone interested in geometric problem-solving techniques.

Dafoe
Messages
7
Reaction score
0
I need help with this one.

http://g.imagehost.org/view/0971/24_p_181


The coloured parts space is limited by three semicircle archs of which the smaller has the radius r.

How should the radius MP be drawn, if you want it to divide the coloured space into two parts with
equally big areas?
 
Last edited by a moderator:
Physics news on Phys.org
What have you tried? Where are you stuck? At first glance, it would look like the most obvious thing would work:

1. Find a convenient way to quantify the position of P
2. Compute a formula for the area of the left blue part
3. Compute a formula for the area of the right blue part
4. Solve for the position of P that makes those areas equal
 
This doesn't require any integration at all. If you draw a vertical downward from M, you cut the blue region into two parts. The area of the left part is 1/4 the area of the large circle plus 1/2 the area of the small circle. What is that?
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
5K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 27 ·
Replies
27
Views
6K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
8K