Solving Mass in Horizontal Pulley System: 99 kg?

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Homework Help Overview

The problem involves a mass on a horizontal surface connected to a hanging mass via a pulley system. The scenario includes a specified acceleration and one known mass, prompting a calculation for the other mass to maintain that acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants suggest using free-body diagrams and Newton's second law to analyze the forces acting on each mass. There are questions regarding the correctness of the initial calculation and the interpretation of the given information.

Discussion Status

Some participants have provided guidance on how to approach the problem through diagramming and applying fundamental physics principles. There appears to be a mix of understanding and confusion regarding the known and unknown variables in the problem.

Contextual Notes

There is mention of the late hour affecting the original poster's clarity, which may influence their reasoning. Additionally, there is a question about whether the known mass is being correctly identified in the context of the problem.

pointintime
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Homework Statement



a mass (m1) on a smooth horizontal surface, connected by a thin cord that passes over a pulley to a second block (m2), which hangs vertically.

If the acceleration is .098 m/s^2 and m1 is 1.0 kg how much must m1 must be to keep it at this acceleration

Homework Equations



net force = ma

The Attempt at a Solution



i got 99 kg
please help me... it's really late at night and I'm tired...
 
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Do what you always should do with mechanics problems: draw free-body diagrams, then write out Newton's second law for each body. Remember that the tension in a massless rope hung over a massless pulley is constant throughout the rope.
 
Draw free-body diagrams of each object and the forces acting on them. If two objects are connected by a single string, then they have the same tension.
 
Do you know if I got it right?
 
your asking for m1? It's already given. Am I right?
 

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