Solving Mechanics Questions: Cyclists A & B, Fly

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SUMMARY

The problem involves two cyclists, A and B, starting from displacements of 0 Km and 70 Km, respectively, cycling towards each other at velocities of 15 Km/hr and 20 Km/hr. A fly, initially on cyclist A, flies towards B at 30 Km/hr, turning around upon reaching each cyclist until they meet. The cyclists will meet after 1.4 hours, covering distances of 21 Km and 49 Km respectively, while the fly will travel a total distance of 42 Km before the cyclists meet.

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Homework Statement



Two cyclists, A and B, have displacements 0 Km and 70 Km, respectively. At t = 0 they begin to cycle towards each other with velocities 15 Km/hr and 20 Km/hr, respectively. At the same time, a fly that was sitting on A starts flying towards B with a velocity of 30 Km/hr. As soon as the fly reaches B it immediately turns around and flies towards A, and so on until A and B meet.

a) What will the displacement of the two cyclists and the fly be when all three meet?

b) What will be the distance traveled by the fly?


Homework Equations



x = ut + 0.5at^2
v^2 = u^2 + 2as
v= at+u

The Attempt at a Solution



attempted a method of graphing but failed and attempted fill in variables in equations but failed again
 
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There is no acceleration in this problem. The two cyclists move with constant velocities.
Try to find out when will they meet. The equations of motions are just
d1=v1*t
d2=v2*t
with the distances measured from A and B respectively.
What is d1+d2 when they meet?
 

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